Find all real roots of:

a. t(x) = 2x^2 -3x -6

b. f(x) = 3x^6+x^3 - 2


Evaluate

-1 - 2i
over or divided by
-5 - 4i

 

you need to do the quadratic equation

and then the bottom im pretty sure you multiply by the reciprical of the denominator so -5+4i and then i^2 = -1

 

i am so glad i am done with school... well until i go back for my MBA...

 

mikietaps best cig evar.

 

a) x= (3+sqrt(57))/4
x= (3-sqrt(57))/4

b) i've taken math all the way up to differential equations where we deal a lot with polynomials and have never once had to solve anything over the 3rd power. tell your teacher they're nuts and go **** themself.

c) (13-6i)/41

 

i kinda got stuck watching mikietaps sig

 

to the second power

 

i tried

you should try dividing by zero

 

seriously. there's no need to do that **** by hand. there are numerical methods that your graphing calc can employ to do that **** way faster than you ever could by hand. your teacher can eat a bag of dicks.

edit: you can actually solve b by breaking x^6 into x^3*x^3 where you treat x^3 as a variable in the second degree polynomial form a(x^3)^2 + b(x^3) + c = f(x) and solve accordingly. I stand behind my original post, though.

 

lol wat math are you in??