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Just Bought This!

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Old May 16, 2005 | 01:16 AM
  #1  
Peteman187's Avatar
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Default Just Bought This!

Just bought this 2 in 1 turbo timer + boost gauge. Anyone have it? Im pumped. Do you think you can change it from hkPa to psi?

http://www.blitz-na.com/Blitz_Turbo_Timer_Dtt.htm
 
Old May 16, 2005 | 01:22 AM
  #2  
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Default RE: Just Bought This!

Doesn't say anything about being able to switch the output to PSI, so I doubt it can be switched.

When I lived in Canada, I could never figure out Kpa, and I don't think anyone can.
 
Old May 16, 2005 | 01:28 AM
  #3  
BFlan2001's Avatar
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Default RE: Just Bought This!


ORIGINAL: david9999

When I lived in Canada, I could never figure out Kpa, and I don't think anyone can.
i'm pretty sure it's been scientifically proven that no one can actually figure out the Kpa system, it's just not possible for us mere mortals
 
Old May 16, 2005 | 01:37 AM
  #4  
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Default RE: Just Bought This!

Hope this helps!


In a Manufacturing and Engineering class, students are instructed to set up a lab to measure the length of an uncompressed Load Spring (L) and then to measure the change in the Load Spring length for various forces. Hooke’s Law states that a spring compresses proportionately to the force placed on it and uses the formula F = (L-L ) K, where L-L is the spring length change and K is the spring rate constant for this direct variation. If instead of doing the lab, you were trying to predict the anticipated change in the spring length for a given pressure, you would need to change the equation so that the spring length change (C) was the dependent variable, the pressure (P) or force was the independent variable, and k was 1/K. The new equation would be C = kP.

1. If the spring length change varies directly with the pressure applied, complete the table below for spring length change using the following measured lab observation of a Load Spring: 150 psi produces a spring length change of 0.381 in.
Write the equation using C for spring length change and P for pressure.
Find the constant of variation k and substitute it into the equation.
Use this equation to calculate the spring length change (in/psi) for each of the given pressures (psi).


Pressure (psi) Change (in/psi) Pressure (kpa) Change (cm/kpa)
150 0.381 1035
200
250
300

2. If a pressure of 150 psi is equivalent to 1035 kpa, find the equivalent pressure in kpa for each of the given pressures in psi.
Write an equation using A for pressure in kpa (dependent variable) and I for pressure in psi (independent variable).
Find the constant of variation k and substitute it into the equation.
Use this equation to calculate the pressure (kpa) for each of the given pressures (psi).

3. Since the spring length varies directly with the pressure applied, complete the last column of the table for spring length change (cm/kpa) for each of the pressures calculated in #2. Use the measured lab values: 1035 kpa produces a spring length change of 0.96774 cm. Follow the steps in #1 above.

4. If the values for in/psi are equivalent to the values for cm/kpa, find the constant of variation that would let you convert from the first to the second.

 
Old May 16, 2005 | 01:48 AM
  #5  
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Default RE: Just Bought This!

damn u i just finished school i dont want to see these confusing problems .... lol
 
Old May 16, 2005 | 01:56 AM
  #6  
skidplatexa4's Avatar
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Default RE: Just Bought This!

Summer classes have now begun. I will be your instructor you can call me Dr.SKIDPLATE haha j/k
 
Old May 16, 2005 | 02:30 AM
  #7  
Yuikio's Avatar
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Default RE: Just Bought This!

5. And do all that **** in your head while you're driving.

I'm not making fun; you are obviously either tres intelligent, or you have some good internet resources.

How about this:
1 psi = 6.895 kiloPascals

1 bar = 14.7 psi
so 1 bar~101.4 kPa. That's math you can do in your head.
 
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